35r^2-52r+12=0

Solution for 35r^2-52r+12=0 equation:

Simplifying
35r2 + -52r + 12 = 0

Reorder the terms:
12 + -52r + 35r2 = 0

Solving
12 + -52r + 35r2 = 0

Solving for variable 'r'.

Factor a trinomial.
(2 + -7r)(6 + -5r) = 0

Subproblem 1
Set the factor '(2 + -7r)' equal to zero and attempt to solve:

Simplifying
2 + -7r = 0

Solving
2 + -7r = 0

Move all terms containing r to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -7r = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -7r = 0 + -2
-7r = 0 + -2

Combine like terms: 0 + -2 = -2
-7r = -2

Divide each side by '-7'.
r = 0.2857142857

Simplifying
r = 0.2857142857
Subproblem 2
Set the factor '(6 + -5r)' equal to zero and attempt to solve:

Simplifying
6 + -5r = 0

Solving
6 + -5r = 0

Move all terms containing r to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -5r = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -5r = 0 + -6
-5r = 0 + -6

Combine like terms: 0 + -6 = -6
-5r = -6

Divide each side by '-5'.
r = 1.2

Simplifying
r = 1.2
Solution
r = {0.2857142857, 1.2}